thezerg
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« on: April 10, 2007, 07:39:51 PM » |
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I can't remember what it is. Anyone want to tell me?
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Chronos
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Make your swords become like things unto chainsaws
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« Reply #1 on: April 10, 2007, 09:16:20 PM » |
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It's
c0 + c1 / 2 + c2 / 6 + ... + cn / (n+n^2)
I believe. At least for the computers.
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thezerg
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« Reply #2 on: April 10, 2007, 11:47:28 PM » |
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gracias
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Chronos
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Make your swords become like things unto chainsaws
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« Reply #3 on: April 12, 2007, 06:00:18 PM » |
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De nada.
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The-Joe
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Aliens got me!
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« Reply #4 on: April 24, 2007, 05:35:38 AM » |
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And computers are stacked automaticly in order (i guess).
35% + 34%(1+2/2)+33%(2+2/3)...
or something close to that. I'm not sure about the order, is it cost, accu, def or what.
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thezerg
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« Reply #5 on: April 24, 2007, 09:41:06 AM » |
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Im pretty sure its auto stacked by %
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Zero3dx
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« Reply #6 on: April 29, 2007, 11:27:24 PM » |
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is this correct for shields?
im trying it and it doesnt really seem to work out the way i want it to....
???
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Gunfighter Frank
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« Reply #7 on: April 30, 2007, 12:30:57 PM » |
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shields are simple 1 shield give full power 2nd sheild give 1/2 power 3rd give 1/3 power do the math then - 3 since you have 3 shields. that is the basics. however if you drop too much from the 1st and 3rd shield the average of the shields will also come into play. IE a 30 and a 10 will give you ~ 20 since the difference in the shield power the average comes into play.
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Gunfighter Frank
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DO or DIE
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SirAlucard
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« Reply #8 on: May 14, 2007, 11:17:52 PM » |
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I'm unfortunately not extremely good at maths, so I have been wondering if anyone could throw me an example
Assuming my computers are all 20% acc.
c0 + c1 / 2 + c2 / 6 + ... + cn / (n+n^2)
20 + 20 / 2 + 20 / 6 + ... + cn / (n+n^2)
What does ... stand for?
What does cn stand for?
What does n stand for?
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thezerg
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« Reply #9 on: May 14, 2007, 11:45:35 PM » |
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... is a math term meaning that the formula goes on until it has reahed the number n. N represents the number of the shield in the system, ie: the 1st shield, the 2nd shield.... I assume that cn is the %.
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SirAlucard
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« Reply #10 on: May 14, 2007, 11:51:31 PM » |
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okay, so I'm intending to run 3 or 4 computers at 20% each. How would I work that out?
20 + 20 / 2 + 20 / ? (n+3^2)
40 22
20 + 20 / 2 + 20 / 6 + 20 / ? (n+4^2)
40 22 26
I have no idea how you guys think 'n' is a number....
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thezerg
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« Reply #11 on: May 15, 2007, 12:24:51 AM » |
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here it is with 4
20 + 20/(1+1^2) + 20/(2+2^2) + 20/(3+3^2)
20 + 20/(2) + 20/(6) + 20/(12)
20 + 10 + 3 1/3 + 1 2/3
= 35%
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SirAlucard
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« Reply #12 on: May 15, 2007, 12:51:08 AM » |
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See and now it's been written out like that my mind understands and can work with it, thankyou muchly!
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Dont blame my main
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« Reply #13 on: May 15, 2007, 05:18:44 AM » |
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Thezerg you might want to look to your formula again as it is incorrect. I could now give you the correct formula but that would ruin the fun, right?
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thezerg
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« Reply #14 on: May 15, 2007, 08:52:32 AM » |
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really, dang. Now I feel stupid. I hadn't used it to design anything yet...
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