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Author Topic: Lammalord's House of Riddles  (Read 167999 times)
Seither
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« Reply #435 on: April 05, 2008, 02:40:51 PM »

HEROINE!!!!

ok..., lol, no idea, didn't even rea dthe riddle....but I had to.
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Chronos
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« Reply #436 on: April 24, 2008, 09:05:05 PM »

16.
199?


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You know what? You know what?

I'm gonna go out on a limb here and say the Golden Ratio (Golden Mean, Golden Proportion, whatever).
« Last Edit: April 25, 2008, 01:55:46 AM by Chronos » Report to moderator   Logged

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« Reply #437 on: April 26, 2008, 09:25:37 PM »

O Lammalord, Lammalord, Wherefore art thou Lammalord?
« Last Edit: April 26, 2008, 10:35:33 PM by Chronos » Report to moderator   Logged

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« Reply #438 on: April 27, 2008, 01:25:56 AM »

O Lammalord, Lammalord, Wherefore art thou Lammalord?
I'll get him. >.>
-Buys some shiny new fleets-
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« Reply #439 on: April 27, 2008, 04:00:49 AM »

6) an animal cracker?
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« Reply #440 on: April 27, 2008, 04:13:36 PM »

riddle #10, they all have two sets of double letters.
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Chronos
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« Reply #441 on: April 27, 2008, 04:14:53 PM »

...Only the first and last ones do.
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Lammalord
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« Reply #442 on: April 28, 2008, 12:58:55 AM »

AHH MY brain!!!!

>.< uhm ill go with da flow..



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Lammalord
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« Reply #443 on: April 28, 2008, 01:07:57 AM »

mmm 9 out of 24 answered right.. i need to find more riddles..

comming soon! (now, im going to bed haha :p)


mmmm edit, link to the house of riddles on youtube (why i havent been paying attention here much lol)

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Chronos
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« Reply #444 on: April 28, 2008, 01:54:17 AM »

Heh, wow, I was right on number sixteen.

It took some thinking. >_<

Basically if you hit every nth point (skipping every n-1 points) on a star of m points, you will touch every point on that star if and only if n is coprime to m.

So you pretty much have to count up all of the numbers coprime to m and less than m (good ol' programming languages making my life easier); subtract one because m-1 is coprime to m, because hitting every (m-1)th is basically drawing a polygon backwards; and then divide that number in half, because for every n that simulates skipping n-1 points in the forward direction, there is a different n that simulates skipping those points in the reverse direction.

Thus, you get:

399,
398,
199.

...And you know what the worst part of all is? I thought that up all on my own.


Warning! Extra high levels of geekiness have been reported in the surrounding area.
Please make sure to keep your emergency survival kit up to date.
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Lammalord
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« Reply #445 on: April 28, 2008, 02:20:53 AM »

mmm well that made it more complicated that it was.. it had something to do with prime number lol in short (i dont wanna explain how)

there are 600 numbers that wont work and 400 that will, now you have to subtract 200 (mirror images) and then 1 wont work thus leaveing 199
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Chronos
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« Reply #446 on: April 28, 2008, 03:06:52 AM »

mmm well that made it more complicated that it was..

Hmm, no. I looked up your answer from the source just now.

Pretty much the only difference between the two approaches is that I used a computer to calculate the number of coprimes and they just looked at the properties of numbers divisible by two and/or five.

In fact, my approach is more useful because I can apply it to a star of any number of points, and, well, let us just say that counting coprimes by hand can get darn pretty messy.
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« Reply #447 on: April 28, 2008, 05:03:50 AM »

Geez Chronos, stop making us all look bad.  16
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« Reply #448 on: April 28, 2008, 04:15:33 PM »

mmmm
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Chronos
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« Reply #449 on: April 28, 2008, 04:19:23 PM »

Geez Chronos, stop making us all look bad.  16


Sorry...
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